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0.07x^2+33x-30=0
a = 0.07; b = 33; c = -30;
Δ = b2-4ac
Δ = 332-4·0.07·(-30)
Δ = 1097.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1097.4}}{2*0.07}=\frac{-33-\sqrt{1097.4}}{0.14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1097.4}}{2*0.07}=\frac{-33+\sqrt{1097.4}}{0.14} $
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